4.3 - Practice problem answers

Keya Jani, Gurdit Sood

Practice Problem Answers #

1. The number of angular nodes is dependent on the value of ℓ. Since it is a p orbital, ℓ = 1, meaning there is 1 angular node.

2. Radial node = n - ℓ -1 Radial node = 4 - 2 -1 Radial node = 1

3. The value for ℓ in this case is 2, because it is a d orbital. Angular node = ℓ Angular node = 1

The angular node is 1 because the p orbital results in ℓ = 1

Radial node = n - ℓ - 1 Radial node = 3 - 1 - 1 Radial node = 1

4. 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s¹

5. 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p²

6. Tin, or Sn